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Frequency

Background 

The requirement is to understand what factors and dependencies cause attenuation in fiber optic.


Initial questions

How is attenuation dependent on frequency?
 
 

Selected problem

All questions were selected to answer in detail.
 
 

My explanation

Attenuation has relation in increasing with frequency, which means the higher the frequency the higher the attenuation.

 

Critical evaluation 

More details and reading as well as reasoning that need to be provided.

 

Finding more information 

More information is obtained by reading books and searching for online information.

 

Final theory

Attenuation is a loss of intensity in an energy beam as it passes through a substance or object or the energy loss of signal transmission through a given medium. Coefficient is a quantitative measure of either an effect or a property. It is the ratio by which a change in one property will change another property. The attenuation coefficient is thus a ratio comparing the loss of intensity to the distance that the energy beam passes through the material. The units used to express the intensity will depend on the precise energy beam. 
The attenuation coefficient is also used in ultrasound. When ultrasound waves propagate in a medium, energy is removed from the ultrasound waves by two main processes, absorption and scattering.The mechanism that removes energy from the ultrasound waves is called “attenuation”. Ultrasound is absorbed by the medium if part of the wave energy is converted into other forms of energy, such as heat. The absorption is frequency dependence. When ultrasound waves propagate, they not only become smaller in amplitude but they also change shape. Absorption in the body has a major effect on the penetration depth. It would limit the detectable penetration of the ultrasound waves in the body or the maximum depth at which tissues can be imaged. The attenuation of ultrasound in a material could be described by the attenuation coefficient in the units of decibels per centimetre per megahertz (dB/cm/MHz). 

Attenuation always serves as a measurement parameter that leads to the formation of theories to explain physical or chemical phenomenon, which decreases the ultrasonic intensity. Attenuation is generally proportional to the square of sound frequency. Quoted values of attenuation are often given for a single frequency, or an attenuation value averaged over many frequencies may be given. The attenuation coefficient (α) can be used to determine total attenuation in dB in the medium using the following formula:

α: attenuation coefficient
 ℓ: medium length
 ƒ: frequency of the incident ultrasound beam

The attenuation coefficients of common biological materials at a frequency of 1 MHz are listed below:

Materialα(dB/(MHz·cm))
Air1.64 (20°C)
Blood0.2
Bone, cortical6.9
Bone, trabecular9.94
Brain0.6
Breast0.75
Cardiac0.52
Connective tissue1.57
Dentin80
Enamel120
Fat0.48
Liver0.5
Marrow0.5
Muscle1.09
Tendon4.7
Soft tissue (average)0.54
Water0.0022

Figure 1. Diffuse reflection. Copied from [1]


 
Reference
 
  1. Culjat, Martin O.; Goldenberg, David; Tewari, Priyamvada; Singh, Rahul S. (2010). "A Review of Tissue Substitutes for Ultrasound Imaging". Ultrasound in Medicine & Biology 36 (6): 861–873.
  2. Tole, Nimrod M. (2005). Basic physics of ultrasonographic imaging. 
    Chapter 3: http://www.isradiology.org/isr/docs_books/basic/Chapter3.pdf
  3. Michael L. Oelzea; William D. O’Brien, Jr. (2002). Frequency-dependent attenuation-compensation functions for ultrasonic signals backscattered from random media.
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Transparency in optical fibers

 

Background

 

The requirement is understand transparency term in optical fiber domain.

 

Initial questions

 

What is transparency in optical fiber?

 

What is the role of transparency in optical fiber study?

 

Selected problem

 

All questions were selected to answer in detail.

 

My explanation

 

Transparency takes an important role for understanding of optical fiber scheme/signal transmitting in optical fibers.

 

Critical evaluation

 

More details and reading as well as reasoning that need to be provided.

 

Finding more information

 

Critical evaluation requires reading more in Fiber optics engineering of Mohammad Azadeh and from reliable online source.

 

Final theory

 

Optical fibers have held a key role in making growth of world-wide communications and internet. The creation of very pure glass which is sufficiently transparent that makes possibility of long distance transmission of light through glass fibers. In 1960, working in research laboratory in California, Theodore Maiman produced the first operating laser which has very pure nature, well-defined color and is very bright. The special properties of laser create opportunities to expand the usefulness of optical communication links. In addition, the creation of a reliable, affordable channel for long distances data transmission is required to advance optical communication. In 1854, in London, John Tyndall shown that light can be guided along a stream of flowing water that proves light needs not to travel in straight lines.[1]

 

 An optical waveguide must be made from a transparent material which can be plastics or glasses. Optical attenuation in plastics is much higher than the attenuation in glasses. Materials such as polystyrene or polymethacrylates (PMMA) are often used plastic fibers with losses in range of 100-1000 dB/km. However, plastic fibers are easy to manufacture so that is an economic solution for short-range communication. Nevertheless, glasses are excellent materials for optical waveguides as those have very low loss.[2,128]

 

Total internal reflection theory was applied in guiding light in optical fibers. When a light ray passes from a transparent medium to another, it bends at the boundary of two media. The bending phenomenon can be described by Snell’s law mathematically:

 

Image Added

 

  n1sinq 1=n2sinq 2          

 

Figure1: Refractive indices of media and Snell’s law. Copied from [1].

 

As figure 1 shows that is n2 is less than n1, there is restriction of the angles that light ray can go cross the border. Light goes from medium 1 to medium 2 with condition that f1 is greater than the critical angle so light cannot refract across the boundary (because f1 cannot greater than 90). The critical angle is defined by sine of n2/n1. A light ray goes to the boundary at an angle which is greater than the critical angle, it reflects and does not cross the border.[1]

 

Image Added

 

Figure 2: Total internal reflection. Copied from [1].

 

Figure 2 shows typical structure of an optical fiber with the capability of guiding light ray inside by applying the total internal reflection between the core glass and the less dense glass surrounding.

 

In 1958, fiber imaging bundles were developed for medical imaging. In that bundle, a large number of optical fibers are bonded together. Optical image is relayed from one end of bundle and appears at the other end, where it can be seen. It was concluded that about 80 percents of the original light is transmitted to other end with a bundle 1m long. However with 100m long bundle, only a ten billionth part of the light reaches the far end. The attenuation of bundle was measured as 1000 dB per km, which can be considered useless for long distance light transmission.[1]

 

In 1966, Charles Kao and George Hockham pointed out that glass attenuation has reason in the impurity with appearance of metal ions, such as iron, copper, vanadium and chromium and a glass with attenuation of 20 dB/km can make 1% of input light reaches the other end of a 1 km-length fiber. In 1979 the attenuation of 0.2 dB/km was achieved in optical fiber.[1] 



References:
 1. http://www.ece.umd.edu/~davis/optfib.html
2. Azadeh, M. (2009). Fiber optics engineering.